Saturday, October 13, 2012

ANOVA (Example)

A researcher wishes to try three different techniques to lower the blood pressure of individuals diagnosed with high blood pressure. The subjects are randomly assigned to three groups: the first group takes medication, and the second group exercise, and the third group follows a special diet. After four weeks, the reduction in each person’s blood pressure is recorded. At α=0.05, test the claim that there is no difference among the means.

The data follows:



Solution:

STEP 1 State the hypothesis and identify the claim.
      H0: µ1 = µ2 = µ3 (claim)
      H1 = At least one mean is different from the others

STEP 2 Find the critical value, since k=3 and N=15,
      d.f.N. = k-1= 3-1 =2
      d.f.D. = N-k= 15-3 =12
The critical value is 3.89, obtained from table H in Appendix C with α = 0.05.

STEP 3 Compute the test value.
            

c. Find the between group variance.


d. Find the within group variance.


e. Find the F test value.


STEP 4 Make the decision. 
             The decision is to reject the null   hypothesis since 9.17>3.89.

STEP 5 Summarize the results. 
There is enough evidence to reject the claim and conclude that at least one mean is different from the other. 



By: Andrea Beatrice Pechueco

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